chocobochicken
08-03-2005, 06:57 AM
I've always had a good head for numbers, but I'm a bit of an amateur when it comes to statistics. This became apparant when I recently began attepting to calculate the odds of completing several consecutive Fake In Yellow runs without finding a single Rappy's Wing (my record so far is 13).
First, I reasoned the formula:
F(x) = 127^(47x)/128^(47x)
where x is the number of FIY runs and F(x) is the % chance that I will not find a single wing.
Now, I'm not exactly certain I have the right equation, but it intuitively feels right to me. This is assuming a drop rate of 1/128 and 47 rappies per run, with what I think is the total number of wingless outcomes divided by the total outcomes. If this is right, then this means I have about a 33% chance to come out empty-handed after 3 consecutive runs (with a 67% chance of finding one or more).
Unfortunately, I can no make calculations with this formula for x>3 because the exponential is too high for the abilities of MS Excel (my tools are limited). So is there a method using logarithms or other mathematical techniques that can simplify this equation, or do I just need to seek bigger number-crunching power?
Math majors, go wild. ^^
First, I reasoned the formula:
F(x) = 127^(47x)/128^(47x)
where x is the number of FIY runs and F(x) is the % chance that I will not find a single wing.
Now, I'm not exactly certain I have the right equation, but it intuitively feels right to me. This is assuming a drop rate of 1/128 and 47 rappies per run, with what I think is the total number of wingless outcomes divided by the total outcomes. If this is right, then this means I have about a 33% chance to come out empty-handed after 3 consecutive runs (with a 67% chance of finding one or more).
Unfortunately, I can no make calculations with this formula for x>3 because the exponential is too high for the abilities of MS Excel (my tools are limited). So is there a method using logarithms or other mathematical techniques that can simplify this equation, or do I just need to seek bigger number-crunching power?
Math majors, go wild. ^^